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You begin with 13.89 grams of CO(g) and 17.83 grams of O 2(g) . If 14.84 grams of CO 2(g) are produced, what is the percent yield? 2 CO(g)+ 1 O 2(g) → 2 CO 2(g)"

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linahamdan1980

Answer:

Explanation:

2CO + O2------ 2CO2

from the conservation of  mass law

mass of CO2 = ( 17.83 + 13.89)= 31.72 g

% yields = Experimental mass / theoretical  mass )x 100%

            =  14.84/31.72 ) x100%

              46.78%

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