Answer:
41.03 %
Explanation:
Given that,
The actual length of a strip of aluminum is 2.12 m
Observed length of a strip of aluminum is 1.25 m
We need to find the student's percent error. The percentage error on any value is given by :
[tex]\%=\dfrac{\text{observed-actual}}{\text{actual}}\times 100[/tex]
Putting all values, we get :
[tex]\%=\dfrac{2.12-1.25}{2.12}\times 100\\\\\%=41.03\ \%[/tex]
So, the percent error of the student is 41.03 %.
