Answer:
444
Step-by-step explanation:
So we know that the sum of four consecutive numbers is 1770.
Let the first number be n,
Then the second number must be (n+1), followed by (n+2) and (n+3).
They sum to 1770, so:
[tex]n+(n+1)+(n+2)+(n+3)=1770[/tex]
Combine like terms:
[tex]4n+6=1770[/tex]
Subtract 6 from both sides:
[tex]4n=1764[/tex]
Divide both sides by 4:
[tex]n=441[/tex]
So, the first number is 441.
So our sequence is 441, 442, 443, and 444.
Thus, our last number is 444.
And we're done!
