[tex] \bf \underline{ \underline{Given : }}[/tex]
- Time taken by freely falling apple = 5.6 seconds
- Initial velocity,u = 0 m/s [ Rest ]
- Acceleration due to gravity,g = 9.8 m/s² [ Constant value ]
[tex] \bf \underline{ \underline{To \: be \: calculated : }}[/tex]
Calculate the height covered by a freely falling apple drop in 5.6 seconds.
[tex] \bf \underline{ \underline{Solution : }}[/tex]
According to the Second equation for free falling body
[tex] \sf{h = ut + \frac{1}{2} gt {}^{2} }[/tex]
[tex] \sf \red\star \: {Substituting \: the \: values}...[/tex]
[tex] \sf\implies \:h = 0 \times 5.6 + \dfrac{1}{ \cancel{2}} \times \cancel{ 9.8} \times {(5.6)}^{2} [/tex]
[tex] \sf\implies \: h = 0 + 4.9 \times 31.36[/tex]
[tex] \sf\implies \: h = 153.66 \: m[/tex]
[tex] \sf\therefore \: Height \: covered \: by \: an \: apple \: is \: 153.66 \: m.[/tex]
