Answer:
The value is [tex]E = 1.1299 *10^{6} N/C [/tex]
Explanation:
From the question we are told that
The radius is [tex]r = 20.0 \ cm = 0.2 \ m[/tex]
The surface charge density is [tex] \sigma = 10.0 \mu C/m^2 = 10.0 *10^{-6} \ C/m^2 [/tex]
The length is [tex]l = 2.0 \ m[/tex]
The distance from the cylinder is [tex]d = 1.5 \ m[/tex]
Generally the electric field is mathematically represented as
[tex]E = \frac{\sigma}{\epsilon_o} [/tex]
Here [tex]\epsilon_o[/tex] is the permittivity of free space with value [tex]\epsilon_o = 8.85*10^{-12} \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2 [/tex]
So
[tex]E = \frac{10.0 *10^{-6}}{8.85*10^{-12} } [/tex]
[tex]E = 1.1299 *10^{6} N/C [/tex]
