Answer:
Solution : Option B, or 9π
Step-by-step explanation:
We are given that y = x, x = 3, and y = 0.
Now assume we have a circle that models the given information. The radius will be x, so to determine the area of that circle we have πx². And knowing that x = 3 and y = 0, we have the following integral:
[tex]\int _0^3[/tex]
So our set up for solving this problem, would be such:
[tex]\int _0^3x^2\pi \:[/tex]
By solving this integral we receive our solution:
[tex]\int _0^3x^2\pi dx,\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=> \pi \cdot \int _0^3x^2dx\\\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1}\\=> \pi \left[\frac{x^{2+1}}{2+1}\right]^3_0\\=> \pi \left[\frac{x^3}{3}\right]^3_0\\\mathrm{Compute\:the\:boundaries}: \left[\frac{x^3}{3}\right]^3_0=9\\\mathrm{Substitute:9\pi }[/tex]
As you can tell our solution is option b, 9π. Hope that helps!
