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in a hydraulic press the cross sectional area of the big cylinder is 0.5 and a load of 600 can be lifted by it using 500 effort .calculate the cross sectional area of the small cylinder
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Respuesta :

Answer:

0.16cm^2

Explanation:

For big cylinder

cross sectional area(A1)=0.5cm^2

load(F1)=600N

For small cylinder

cross sectional area(A2)=?

load(F2)=500

according to hydraulic press,

F1/A1=F2/A2

600/0.5=500/A2

A2=0.16

shayleeherzberg
The answer is 0.16cm^2

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