Answer:
[tex] \boxed{\sf Final \ speed \ of \ the \ car = 16 \ m/s} [/tex]
Given:
Initial speed (u) = 10 m/s
Acceleration (a) = 2 m/s²
Time taken (t) = 3s
To Find:
Final speed (v) of the car
Explanation:
From equation of motion we have:
[tex] \boxed{ \bold{v = u + at}}[/tex]
By substituting value of u, a & t in the equation we get:
[tex]\sf \implies v = 10 + 2\times 3 \\ \\ \sf \implies v = 10 + 6 \\ \\ \sf \implies v = 16 \: m {s}^{ - 1} [/tex]
[tex] \therefore [/tex]
Final speed (v) of the car = 16 m/s
