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A spring of force constant 45 N/m is used to pull a block along a level surface at: constant speed. The spring is observed to stretch 12.0 cm while supplying this force. How much force is applied?

Respuesta :

Answer:

[tex]F=5.4 N[/tex]

Explanation:

Given:

                 [tex]k=45N/m\\x=12*10^\power{-2}m\\[/tex]

From Hook's law

                 [tex]F= kx\\F=45*12*10^\powe{-2}\\F=5.4 N[/tex]

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