Answer:
The value is [tex]\lambda = 1.329 *10^{-9} \ m[/tex]
Explanation:
From the question we are told that
The orbital radius is [tex]r = 0.846nm = 0.846 *10^{-9} \ m[/tex]
Generally the de Broglie wavelength is mathematically represented as
[tex]\lambda = \frac{2 * \pi r}{4}[/tex]
substituting values
[tex]\lambda = \frac{ 2 * 3.142 * 0.846 *10^{-9}}{4}[/tex]
[tex]\lambda = 1.329 *10^{-9} \ m[/tex]
