Answer:
[tex] \boxed{\sf Acceleration \ (a) = -2 \ m/s^2} [/tex]
Given:
Initial velocity (u) = 20 m/s
Final velocity (v) = 10 m/s
Time taken (t) = 5 seconds
To Find:
Acceleration (a) of the car
Explanation:
From equation of motion we have:
[tex] \boxed{ \bold{v = u + at}}[/tex]
By substituting value of v, u & t in the equation we get:
[tex] \sf \implies 10 = 20 + 5a \\ \\ \sf \implies 5a + 20 = 10 \\ \\ \sf \implies 5a = 10 - 20 \\ \\ \sf \implies 4a = - 10 \\ \\ \sf \implies a = - \frac{10}{5} \\ \\ \sf \implies a = - 2 \: m {s}^{ - 2} [/tex]
[tex] \therefore[/tex]
Acceleration (a) of the car = -2 m/s²
