Answer:
3.3 kg-m/s
Explanation:
The mass of the ball m = 0.08 kg
speed [tex]v_{1}[/tex] = 29 m/s
angle oat which its strikes the wall = 45°
Final speed of rebound[tex]v_{2}[/tex] = 29 m/s
angle of rebound = 45°
Momentum before collision [tex]p_{1}[/tex] = m[tex]v_{1}[/tex] cos ∅
==> 0.08 x 29 cos 45 = 1.64 kg-m/s
since the same variables are maintained in the rebound, then the momentum of rebound will be of the same magnitude, but in the opposite direction
[tex]p_{2}[/tex] = -1.64 kg-m/s
The impulse is the change of momentum [tex]I[/tex] = [tex]p_{1}[/tex] - [tex]p_{2}[/tex]
[tex]I[/tex] = 1.64 - (-1.64 ) = 1.64 + 1.64 = 3.3 kg-m/s
