Make a table of values for f(x) = 18x2 + 10x + 1.

Answer/step-by-step explanation:
To make a table of values, substitute each value of x into the given equation function [tex] f(x) = 18x^2 + 10x + 1 [/tex]
For x = -3,
[tex] f(-3) = 18(-3)^2 + 10(-3) + 1 [/tex]
[tex] f(-3) = 18(9) + (-30) + 1 [/tex]
[tex] f(-3) = 162 - 30 + 1 = 133 [/tex]
For x = -2,
[tex] f(-2) = 18(-2)^2 + 10(-2) + 1 [/tex]
[tex] f(-2) = 18(4) + (-20) + 1 [/tex]
[tex] f(-2) = 72 - 20 + 1 = 53 [/tex]
For x = -1,
[tex] f(-1) = 18(-1)^2 + 10(-1) + 1 [/tex]
[tex] f(-1) = 18(1) + (-10) + 1 [/tex]
[tex] f(-1) = 18 - 10 + 1 = 9 [/tex]
For x = 0,
[tex] f(0) = 18(0)^2 + 10(0) + 1 [/tex]
[tex] f(0) = 18(0) + 0 + 1 [/tex]
[tex] f(0) = 0 - 0 + 1 = 1 [/tex]
For x = 1,
[tex] f(1) = 18(1)^2 + 10(1) + 1 [/tex]
[tex] f(1) = 18(1) + 10 + 1 [/tex]
[tex] f(1) = 18 + 10 + 1 = 29 [/tex]
For x = 2,
[tex] f(2) = 18(2)^2 + 10(2) + 1 [/tex]
[tex] f(2) = 18(4) + 20 + 1 [/tex]
[tex] f(2) = 72 + 20 + 1 = 93 [/tex]
For x = 3,
[tex] f(3) = 18(3)^2 + 10(3) + 1 [/tex]
[tex] f(3) = 18(9) + 30 + 1 [/tex]
[tex] f(3) = 162 + 30 + 1 = 193 [/tex]