contestada

It took a squirrel 0.50\,\text s0.50s0, point, 50, start text, s, end text to run 5.0\,\text m5.0m5, point, 0, start text, m, end text leftward to a nearby tree while maintaining a constant acceleration. The squirrel was running 15\,\dfrac{\text m}{\text s}15 s m ​ 15, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction leftward when it reached the tree.

Respuesta :

Answer:

-5

Explanation:

khan academy

The squirrel's initial velocity is 5m/s.

What is acceleration?

Acceleration is given by the ratio of Resultant or total force acting on any object and the its mass.

It can also be defined as the rate change of velocity with time.

acceleration a = (Δv) / (Δt)

It took a squirrel 0.50 s to run 5.0 meters leftward to a nearby tree while maintaining a constant acceleration. The squirrel was running 15 m/s leftward when it reached the tree.

From the first equation of motion,

v = u+at

15 = u+0.5a

u = 15 - 0.5a.............(1)

From third equation of motion

v² = u² +2as

Putting the values, we have

15² = u² + 2a x 5

225 =  u² +10a

From equation (1), we get

225 =(15 - 0.5a)² +10 a

0.25a² = 5a

a = 20 m/s²

Plug the value in the equation (1), then

u = 15 - (0.5 x 20)

u = 5 m/s

Thus, the initial velocity is 5 m/s.

Learn more about acceleration.

https://brainly.com/question/12550364

#SPJ2

Otras preguntas