I just really need some help

Answer:
-7 and 10
Step-by-step explanation:
[tex]2x^2-6x-140=0[/tex]
Divide both sides by 2
[tex]x^2-3x-70=0[/tex]
From the possible solutions given, we know this equation can easily be factored.
[tex](x-10)(x+7)=0[/tex]
[tex]\therefore x_1=-7 \text{ and } x_2=10[/tex]