Answer:
[tex](f-g)(x)=7x^2+5x-10[/tex]
Step-by-step explanation:
So we have the two functions:
[tex]f(x)=4x^2+3x-5\text{ and } g(x)=-3x^2-2x+5[/tex]
And we want to find (f-g)(x).
This is the same thing to f(x)-g(x).
So, substitute:
[tex](f-g)(x)=f(x)-g(x)\\=(4x^2-3x-5)-(-3x^2-2x+5)[/tex]
Distribute the negative:
[tex]=(4x^2+3x-5)+(3x^2+2x-5)[/tex]
Combine like terms:
[tex]=(4x^2+3x^2)+(3x+2x)+(-5-5)[/tex]
Add or subtract:
[tex]=7x^2+5x-10[/tex]
And we're done!
I hope this helps!