Answer:
m∠ADB = 155°
Step-by-step explanation:
m∠ADB = (m∠C)/2 + 90° = 130°/2 + 90°
m∠ADB = 155°
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Reference https://brainly.com/question/17443119 for the derivation.
Answer:
∠ADB=155°.
Step-by-step explanation:
In Δ ABC, let A = x°
By angle-sum property.
A+B+C=180°
But, it is given that C=130°
So, x+B+130=180
B=180-130-x
B=50-x
Since AD and BD are internal bisectors of A and B,
∠DAB=x/2 and
∠DBA=
In ΔADB, by angle-sum property,
∠DBA+∠DAB+∠ADB=180°
+∠ADB=180°
25+∠ADB=180°
∠ADB=180-25=155°
Hence, ∠ADB=155°.
