Answer:
The temperature drop in both Centigrade and Kelvin are the same:
[tex]19.44^o\,C[/tex], and [tex]19.44\,K[/tex]
Explanation:
Start by converting 35 F and 0 F (the ends of the temp change) into Centigrades using the formula:
[tex]T_C=(F-32)\,\frac{5}{9} \\T_C=(35-32)\,\frac{5}{9}\\T_C=3\,*\frac{5}{9}\\T_C= \frac{15}{9} \,C[/tex]
For 0 F:
[tex]T_C=(0-32)\,\frac{5}{9} \\T_C=(-32)\,\frac{5}{9}\\T_C=-32\,*\frac{5}{9}\\T_C= -\frac{160}{9} \,C[/tex]
now, the difference of these two values is:
[tex]\frac{15}{9} -(-\frac{160}{9} )=\frac{175}{9} \approx 19.44^o\,C[/tex]
Then if the temperature was [tex]80^o C[/tex], then the new temperature is:
[tex]80^o\,C - 19.44 ^o\,C = 60.56^o\,C[/tex]
And since the Kelvin scale differences are the same as the differences in the Centigrade scale, the temperature change in Kelvin is of the same magnitude:
[tex]19.44\,K[/tex]
