Answer:
( x+2) ^2 +(y-3)^2=4^2
The center is ( -2,3) and the radius is 4
Step-by-step explanation:
x^2+4x+y^2-6y-3=0
Add 3 to each side
x^2+4x+y^2-6y=3
Complete the square for x
4/2 = 2 2^2 = 4 so add 4 to each side
x^2+ 4x +4+y^2-6y=3+4
( x+2) ^2 +y^2-6y=7
Complete the square for y
-6/2 = -3 (-3) ^2 = 9 so add 9 to each side
( x+2) ^2 +y^2-6y +9=7+9
( x+2) ^2 +(y-3)^2=16
( x+2) ^2 +(y-3)^2=4^2
The standard equation of a circle is
(x – h)^2 + (y – k)^2 = r^2 where ( h,k) is the center and r is the radius
