Answer:
Minimum volume of water = 0.28 ml
Mass remaining in solution at 25°C = 0.156 g
Maximum mass of sodium benzoate that can be recovered = 0.044 g
Explanation:
solubility of sodium benzoate in boiling water (100°C) = 1 g/1.4 mL
minimum volume of boiling water required to dissolve 0.200 g of sodium benzoate = mass / solubility
minimum volume of water = 0.200 g / (1 g / 1.4 mL)
minimum volume of water = 0.28 ml
Solubility of sodium benzoate at 25°C = 1 g / 1.8 mL
Mass in solution = solubility x volume
Mass in solution = (1 g / 1.8 mL) x 0.28 mL
Mass remaining in solution at 25°C = 0.156 g
Maximum mass of sodium benzoate that can be recovered = 0.200 g -
0.156 g
Maximum mass of sodium benzoate that can be recovered = 0.044 g
