[tex] \bf \underline{ \underline{Given : }}[/tex]
[tex] \bf \underline{ \underline{To \: be \: calculated : }}[/tex]
Calculate the width of the patio.
[tex] \bf \underline{ \underline{Solution : }}[/tex]
Let the width be a.
Then,Length = 4a
According to the question,
[tex] \sf \: Area \: of \: rectangle = 5000 \: ft {}^{2} [/tex]
[tex] \sf \implies \: Length \times Width = 5000[/tex]
Substituting the values of Length and width, we get..
[tex] \sf \implies 4a \times a = 5000[/tex]
[tex] \sf \implies4 {a}^{2} = 5000[/tex]
[tex] \sf\implies \: {a}^{2} = \cancel \dfrac{5000}{4} [/tex]
[tex] \sf\implies \: {a}^{2} = 1250[/tex]
[tex] \sf \implies \: a = \sqrt{1250} [/tex]
[tex] \sf \implies \: a = 35.35 \: \: (approx)[/tex]
[tex] \sf\therefore \: The \: width \: of \: rectangular \: patio \: is \: 35.35 \: ft[/tex]
