Answer:
4 or 5.
Step-by-step explanation:
Let the numbers be represented by x and y.
x * x = mc
y * y = zq
m - c < 10
z - q < 10
x - y = 1
x + y > 7
Let's start from 0.
0
squared: 0, wrong; a new number is meant to be formed.
1
squared: 1, wrong; a new number is meant to be formed.
2
squared: 4, maybe this can work; a new number is formed.
3
squared: 9, maybe this can work; a new number is formed.
4
squared: 16, maybe this can work; a new number is formed.
5
squared: 25, maybe this can work; a new number is formed.
6
squared: 36, maybe this can work; a new number is formed.
7
squared: 49, maybe this can work; a new number is formed.
8
squared: 64, maybe this can work; a new number is formed.
9
squared: 81, maybe this can work; a new number is formed.
FROM HERE, 0 & 1 ARE OUT.
THE QUESTION STATES THAT THE DIFFERENCE BETWEEN THE TWO ORIGINAL NUMBERS WAS ONE.
NOW WE HAVE 2, 3, 4, 5, 6, 7, 8, & 9.
2 & 3.
THE DIFFERENCE BETWEEN THEIR SQUARES SHOULD BE LESS THAN 10 IF THEY CAN WORK.
3^2 - 2^2
9 - 4 = 5; there's a possibility for this to work since the difference of their squares is less than 10.
3 & 4.
THE DIFFERENCE BETWEEN THEIR SQUARES SHOULD BE LESS THAN 10 IF THEY CAN WORK.
4^2 - 3^2
16 - 9 = 7; there's a possibility for this to work since the difference of their squares is less than 10.
4 & 5.
THE DIFFERENCE BETWEEN THEIR SQUARES SHOULD BE LESS THAN 10 IF THEY CAN WORK.
5^2 - 4^2
25 - 16 = 9; there's a possibility for this to work since the difference of their squares is less than 10.
5 & 6.
THE DIFFERENCE BETWEEN THEIR SQUARES SHOULD BE LESS THAN 10 IF THEY CAN WORK.
6^2 - 5^2
36 - 25 = 11, THIS IS WRONG.
6 & 7.
THE DIFFERENCE BETWEEN THEIR SQUARES SHOULD BE LESS THAN 10 IF THEY CAN WORK.
7^2 - 6^2
49 - 36 = 13, THIS IS WRONG.
7 & 8.
THE DIFFERENCE BETWEEN THEIR SQUARES SHOULD BE LESS THAN 10 IF THEY CAN WORK.
8^2 - 7^2
64 - 49 = 15, THIS IS WRONG.
8 & 9.
THE DIFFERENCE BETWEEN THEIR SQUARES SHOULD BE LESS THAN 10 IF THEY CAN WORK.
9^2 - 8^2
81 - 64 = 17, THIS IS WRONG
THE POSSIBLE NUMBERS ARE 2&3, 3&4, AND 4&5.
THE QUESTION STATES THAT THE TWO ORIGINAL NUMBERS ADDED TOGETHER WAS MORE THAN 7.
2&3
2 + 3 = 5, WRONG, THE ADDITION OF THE TWO ORIGINAL NUMBERS SHOULD BE MORE THAN 7 FOR THIS TO WORK.
3&4
3 + 4 = 7, WRONG, THE ADDITION OF THE TWO ORIGINAL NUMBERS SHOULD BE MORE THAN 7 FOR THIS TO WORK.
4&5
4 + 5 = 9, CORRECT, THE ADDITION OF THE TWO ORIGINAL NUMBERS IS MORE THAN 7.
Therefore, the possible numbers are 4 & 5. All that is left is for you to pick which of the two is the final answer if you have options.
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