Answer:
[tex]\bigl(\frac{3}{2},-5\bigr)[/tex]
or in decimal form
[tex](1.5,-5)[/tex]
Step-by-step explanation:
The midpoint of the line with endpoints [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is [tex]\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)[/tex]. just take the average between the points
so given the points (1,0) and (2,-10)
[tex]x_1=1[/tex]
[tex]y_1=0[/tex]
[tex]x_2=2[/tex]
[tex]y_2=-10[/tex]
the midpoint is found as follows:
[tex]\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)[/tex]
[tex]\bigl(\frac{1+2}{2},\frac{0-10}{2}\bigr)[/tex]
[tex]\bigl(\frac{3}{2},\frac{-10}{2}\bigr)[/tex]
[tex]\bigl(\frac{3}{2},-5\bigr)[/tex]
or in decimal form
[tex](1.5,-5)[/tex]
