Respuesta :
Answer: f(x) = 9 pesos if 0km ≤ x ≤ 4km
f(x) = 9 pesos + (x - 4km)*0.75 pesos if 4km ≤ x
Step-by-step explanation:
Ok, we know that:
For the first 4km, we have a fixed price of 9 pesos.
For any km after the 4km mark, we have an extra of 0.75 pesos.
Then if x is the number of kilometers, we can write this as:
f(x) = 9 pesos if 0km ≤ x ≤ 4km
f(x) = 9 pesos + (x - 4km)*0.75 pesos if 4km ≤ x
Where we use (x - 4km) because we start counting after the 4km mark.
The piece-wise function that models the fare in terms of the distance is:
[tex]F(d) = 9, d \leq 4[/tex]
[tex]F(d) = 9 + 0.75(d - 4), d > 4[/tex]
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- A piece-wise function is a function defined by parts, that is, a function that has different definitions depending on the input value.
- For the first 4 kilometres, the fare has a constant price of 9 pesos, thus, the definition of the function is:
[tex]F(d) = 9, d \leq 4[/tex]
- Each additional kilometre after 4 kilometres is quantified by d - 4, price of 0.75 pesos for each of them, plus the 9 pesos of the first four kilometres, thus, for distances more than 4 kilometres, the definition is:
[tex]F(d) = 9 + 0.75(d - 4), d > 4[/tex]
Combining the two definitions, the piece-wise function is:
[tex]F(d) = 9, d \leq 4[/tex]
[tex]F(d) = 9 + 0.75(d - 4), d > 4[/tex]
A similar problem is given at https://brainly.com/question/21890586