Answer:
Area=[tex]a^2+11a[/tex]
Step-by-step explanation:
area=length times width
squares have the same side length, or length=width
in this problem, the side length of the square is [tex]a[/tex]
therefore, length=width=[tex]a[/tex]
the length is increased by 11 to make a rectangle
therefore, the new length is [tex]a+11[/tex]
the width stays the same, it is still [tex]a[/tex]
therefore, the area of the rectangle is length X width=(a+11)*a
Area=(a+11)(a)
use distributive property ([tex]a(b+c)=ab+ac[/tex])
Area=(a)(a)+(11)(a)
Area=[tex]a^2+11a[/tex]
