Answer:
[tex]\huge\boxed{\sf y = \frac{41}{5} \ OR \ y = 8\frac{1}{5} }[/tex]
Step-by-step explanation:
[tex]\sf 2y-15 = \frac{7}{5} \\\\Adding \ 15 \ to \ both \ sides\\\\2y = \frac{7}{5} + 15\\\\2y = \frac{7+75}{5} \\\\2y = \frac{82}{5} \\\\Dividing \ both \ sides \ bu 2\\\\y = \frac{82}{5*2} \\\\y = \frac{41}{5}[/tex]
Hope this helped!