Answer:
[tex]\huge\boxed{\sf S = 0, P = -16}[/tex]
Step-by-step explanation:
Given the equation:
[tex]\sf x^2 -16 = 0[/tex]
Comparing it with [tex]\sf x^2-Sx+P= 0[/tex], where S is the sum and P is the product.
So,
Sum = S = 0
Product = P = -16
Hope this helped!