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Michael has 3 quarters, 2 dimes, and 3 nickels in his
pocket. He randomly draws two coins from his pocket,
one at a time, and they are both dimes. He says the
probability of that occurring is because 2 of the 8
coins are dimes. Is he correct? Explain.

Respuesta :

tramserran

Answer:  Probability = 1/28

Step-by-step explanation:

   First Coin         Second Coin

[tex]\dfrac{2\ dimes}{8\ total\ coins}\times \dfrac{1\ remaining\ dime}{7\ remaining\ coins}\quad =\dfrac{2}{56}\quad \longrightarrow \dfrac{1}{28}(simplified)[/tex]

Sample Response: No. Choosing two dimes are dependent events. The probability of choosing the first dime is 14 and the probability of choosing the second dime is 17 . The probability that both coins are dimes is (14)(17) = 128.

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