Respuesta :
Given that:
Total number of fish = 140
Fish are green swordtails female = 44
Fish are green swordtails male = 36
Fish are orange swordtails female = 36
Fish are orange swordtails male = 24
Solution:
A. We have to find the probability that the selected fish is a green swordtail.
[tex]\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}[/tex]
[tex]\text{P(green swordtail)}=\dfrac{80}{140}[/tex]
[tex]\text{P(green swordtail)}=\dfrac{4}{7}[/tex]
Therefore, the probability that the selected fish is a green swordtail is [tex]\dfrac{4}{7}.[/tex]
B. We have to find the probability that the selected fish is male.
[tex]\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}[/tex]
[tex]\text{P(Male fish)}=\dfrac{36+24}{140}[/tex]
[tex]\text{P(Male fish)}=\dfrac{60}{140}[/tex]
[tex]\text{P(Male fish)}=\dfrac{3}{7}[/tex]
Therefore, the probability that the selected fish is a male, is [tex]\dfrac{3}{7}.[/tex]
C. We have to find the probability that the selected fish is a male green swordtail.
[tex]\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}[/tex]
[tex]\text{P(Male green swordtail)}=\dfrac{36}{140}[/tex]
[tex]\text{P(Male green swordtail)}=\dfrac{9}{35}[/tex]
Therefore, probability that the selected fish is a male green swordtail is [tex]\dfrac{9}{35}.[/tex]
D.
We have to find the probability that the selected fish is either a male or a green swordtail.
[tex]\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}[/tex]
[tex]\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}[/tex]
[tex]\text{P(Male or green swordtail)}=\dfrac{96}{140}[/tex]
[tex]\text{P(Male or green swordtail)}=\dfrac{24}{35}[/tex]
Therefore, the probability the selected fish is either a male or a green swordtail is [tex]\dfrac{24}{35}.[/tex]
