y is inversely proportional to a^3. When a=2, y=10. a is directly proportional to x. When x=4, a=20. Find a formula for y in terms of x. Give your answer in simplest form

Respuesta :

Answer:

y = 16/25x³

Step-by-step explanation:

If y is inversely proportional to a^3, this is expressed as;

y∝1/a³

y = k/a³ where k is the proportionality constant

Given a=2, y=10, then 10 = k/2³

k = 10*2³

k = 80

Substituting k = 80 back into the formula;

y = 80/a³ ............. 1

Similarly, if a is directly proportional to x, then a ∝ x i.e a = kx

If x=4, a=20 then;

20 = 4k

k = 20/4

k = 5

Substituting k = 5 back into the formula;

a = 5x ....... 2

Substitute equation 2 into 1;

y = 80/a³

y = 80/(5x)³

y = 80/125x³

y = 16/25x³

Hence the formula for y in terms of x is y = 16/25x³

If y is inversely proportional to a³ and a is directly proportional to x. Then the relation between y and x is,

[tex]\rm y = \dfrac{16}{25x^3}[/tex]

What is a function?

The function is an expression, rule, or law that defines the relationship between one variable to another variable. Functions are ubiquitous in mathematics and are essential for formulating physical relationships.

y is inversely proportional to a³.

Then we have

[tex]\rm y \propto \dfrac{1}{a^3}\\\\y = \dfrac{k}{a^3}[/tex]

When a = 2, y = 10. Then we have

[tex]\rm k = y a^3\\\\k = 10 * 2^3\\\\k = 80[/tex]

Then y will be

[tex]\rm y = \dfrac{80}{a^3}[/tex] ...1

a is directly proportional to x.

[tex]\rm a \propto x \\\\a = cx[/tex]

When x = 4, a = 20.

[tex]20 = 4c \\\\c \ = 5[/tex]

Then a will be

[tex]\rm a = 5x[/tex] ...2

Put equation 2 in equation 1. Then we have

[tex]\rm y = \dfrac{80}{(5x)^3}\\\\\\y = \dfrac{16}{25x^3}[/tex]

More about the function link is given below.

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