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Una caja de 50 kg es tirada 40 a lo largo del piso por una persona que ejerce una fuerza constante de 100 n formando una u angulo de 37° con la horizontal. La superficie es áspera y ejerce una fuerza de roce de 50 n. Calcule el trabajo efectuado por cada fuerza que actua sobre la caja y el trabajo neto

Respuesta :

Answer:

The work done by the applied force is 3194.54 J.

The work done by the frictional force is -2000 J.

The work done by the gravitational force is zero.

The net work done on the box is 1194.54 J.

Explanation:

Given that,

Mass of box = 50 kg

Constant force = 100 N

Displacement = 40 m

Angle = 37 °

Friction force = 50 N

We need to calculate the work done by the person

Using formula of work done

[tex]W=Fx\cos\theta[/tex]

Put the value into the formula

[tex]W=100\times40\cos37[/tex]

[tex]W=3194.54\ J[/tex]

We need to calculate the work done by the friction force

Using formula of work done

[tex]W=F_{f}x\cos\theta[/tex]

Put the value into the formula

[tex]W=50\times40\cos180[/tex]

[tex]W=-2000\ J[/tex]

We need to calculate the gravitational force

The work done by the gravitational force is zero.

We need to calculate the net work done on the box

Using formula of for net work done

[tex]W'=W+W_{f}+W_{g}[/tex]

Put the value into the formula

[tex]W'=3194.54-2000+0[/tex]

[tex]W'=1194.54\ J[/tex]

Hence, The work done by the applied force is 3194.54 J.

The work done by the frictional force is -2000 J.

The work done by the gravitational force is zero.

The net work done on the box is 1194.54 J.

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