Answer:
[tex]\huge\boxed{\sf 3,5 \ and \ 7}[/tex]
Step-by-step explanation:
[tex]\sf Let \ the \ 3 \ consecutive \ odd \ integers \ be \ x , x +2 \ and \ x+ 4\\\\The \ given \ condition \ is:\\\\x+x+2+x+4 = 15\\\\3x+6 = 15\\\\3x = 15-6\\\\3x = 9\\\\Dividing \ both \ sides \ by \ 3\\\\x = 3\\\\ \underlined{So, the \ 3 \ consecutive \ integers\ are :}\\\\x = 3\\\\x + 2 = 3+2= 5\\\\x+4 = 3+4 = 7[/tex]
Hope this helped!
