Given :
A pipe can make with the horizontal. the minimum angle being 1/4 inch the maximum angle being 1/2 inch .
To Find :
The minimum and maximum angles to the nearest tenth of a degree that a pipe can make with the horizontal.
Solution :
Angle [tex]\theta[/tex] is given by :
[tex]tan\ \theta=\dfrac{opp}{adj}[/tex]
Now , minimum angle is given by :
[tex]tan\ \theta_{min}=\dfrac{\dfrac{1}{4}}{12}=0.02\\\\\theta_{min}=tan^{-1}(0.02)\\\\\theta_{min}=1.146^o[/tex]
For maximum angle :
[tex]tan\ \theta_{max}=\dfrac{\dfrac{1}{2}}{12}=0.04\\\\\theta_{max}=tan^{-1}(0.04)\\\\\theta_{max}=2.291^o[/tex]
Therefore , minimum and maximum angle is 1.146° and 2.291° respectively .
Hence , this is the required solution .
