Answer:
[tex]2PO_4^{3-}(aq)+3Ni^{2+}(aq)\rightarrow Ni_3(PO_4)_2(s)[/tex]
Explanation:
Hello,
In this case, the molecular chemical reaction is:
[tex](NH_4)_3PO_4(aq)+NiBr_2(aq)\rightarrow NH_4Br(aq)+Ni_3(PO_4)_2(s)[/tex]
Thus, by considering the ionic species we have:
[tex]NH_4^+(aq)+2PO_4^{3-}(aq)+3Ni^{2+}(aq)+Br^-(aq)\rightarrow NH_4^+(aq)+Br^-(aq)+Ni_3(PO_4)_2(s)[/tex]
Wherein the ammonium and bromide ions are spectator ions since nickel (II) phosphate is largely insoluble in water, therefore, the net ionic equation is:
[tex]2PO_4^{3-}(aq)+3Ni^{2+}(aq)\rightarrow Ni_3(PO_4)_2(s)[/tex]
Best regards.