Answer:
[tex]-\sqrt{\dfrac{1}{16}}[/tex]
Step-by-step explanation:
First we have to find the decimal form of each quantity.
[tex]-\dfrac{1}{12}=-0.0833...\approx -0.083[/tex]
[tex]-0.12[/tex]
[tex]-\sqrt{\dfrac{1}{16}}=-\dfrac{1}{4}=-0.25[/tex]
[tex]-0.08[/tex]
Now, arrange the values in the ascending order.
[tex]-0.25,-0.12,-0.083, -0.08[/tex]
Here the smallest quantity is -0.25 which is [tex]-\sqrt{\dfrac{1}{16}}[/tex].
Therefore, the smallest quantity is [tex]-\sqrt{\dfrac{1}{16}}[/tex].