Respuesta :
Answer:
H = 63536J
Explanation:
mass = 200g
Initial Temperature = 24°C
Final Temperature = 100 °C
ΔT = Final - Initial = 100 - 24 = 76°C
Specific heat, c = 4.18 J/g∙C
Heat, H = ?
All these parameters are related by the equation;
H = mcΔT
Inserting the values;
H = 200 * 4.18 * 76
H = 63536J
The heat that must be added is 63,536 J
What is Specific Heat ?
It is the quantity of heat required to raise the temperature of one gram of a substance by one Celsius degree. The units of specific heat are usually calories or joules per gram per Celsius degree.
Q = mc ΔT
It is given that the mass os water is 200 grams ,
Initial Temperature = 24 degree Celsius
Final Temperature = 100 degree Celsius
c = 4.18 J/g∙C
Q is the heat added which will be equal to
Q = 200 * 4.18 * 76
Q = 63,536J
Therefore the heat that must be added is 63,536 J.
To know more about Specific Heat
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