Answer:
P(Z < 2.37) = 0.9911.
Step-by-step explanation:
We are given that Let z denote a random variable that has a standard normal distribution.
Let Z = a random variable
So, Z ~ Standard Normal(0, 1)
As we know that the standard normal distribution has a mean of 0 and variance equal to 1.
Z = [tex]\frac{X-\mu}{\sigma}[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = mean = 0
[tex]\sigma[/tex] = standard deviation = 1
Now, the probability that z has a value less than 2.37 is given by = P(Z < 2.37)
P(Z < 2.37) = P(Z < [tex]\frac{2.37-0}{1}[/tex] ) = P(Z < 2.37) = 0.9911
The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.9911.
