Respuesta :
Answer:
[tex]60[/tex] heartbeats per minute
Step-by-step explanation:
Let the normal heartbeats of the bear is [tex]x[/tex] heartbeats per minute.
Given that the dropped heart rate is [tex]12[/tex] heartbeats which is [tex]20 \%[/tex] of the normal heartbeat. This can ve written in the form of the equation as
[tex]12= 20\%[/tex] of [tex]x[/tex]
[tex]\Rightarrow 12=\frac {20}{100}\times x[/tex]
[tex]\Rightarrow x= \frac {12\times 100}{20}[/tex]
[tex]\Rightarrow x=60.[/tex]
Hence, the normal heartbeats of the bear is [tex]60[/tex] heartbeats per minute
Answer:
60 beats per minute
Step-by-step explanation:
12 Heartbeats per minute during hibernation is 20 percent of the normal value.
Let X be the normal heartbeat,
So, as per the question
20% of X = 12
20/100 * X = 12
Hence X = 60
So, the normal heartbeat of the beer is 60 beats per minute.
