Answer:
B: [tex]x>\frac{3}{2}[/tex]
Step-by-step explanation:
[tex]12\left(\frac{1}{2}x-\frac{1}{3}\right)>8-2x[/tex]
Expand:
[tex]6x-4>8-2x[/tex]
Add 4 to both sides:
[tex]6x-4+4>8-2x+4[/tex]
[tex]6x>-2x+12[/tex]
Add 2x to both sides:
[tex]6x+2x>-2x+12+2x[/tex]
[tex]8x>12[/tex]
Divide both sides by 8:
[tex]\frac{8x}{8}>\frac{12}{8}[/tex]
Hence, [tex]x>\frac{3}{2}[/tex] (Option B)
