how to do this 4 question
help asap pls

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a) 2^(-1) = 1/2
a) 2^(-1) = 1/2b) 2^(-3) = 1/2^3
a) 2^(-1) = 1/2b) 2^(-3) = 1/2^3 = 1/8
a) 2^(-1) = 1/2b) 2^(-3) = 1/2^3 = 1/8c) 2^(-2) = 1/2^2
a) 2^(-1) = 1/2b) 2^(-3) = 1/2^3 = 1/8c) 2^(-2) = 1/2^2 = 1/4
a) 3^(-2) = 1/ 3^2
a) 3^(-2) = 1/ 3^2 = 1/ 9
a) 3^(-2) = 1/ 3^2 = 1/ 9b) 2^(-3) = 1/ 2^3
a) 3^(-2) = 1/ 3^2 = 1/ 9b) 2^(-3) = 1/ 2^3 = 1/8
a) 3^(-2) = 1/ 3^2 = 1/ 9b) 2^(-3) = 1/ 2^3 = 1/8c) 6^(-1) = 1/6
a) 2^2 + 2^0 + 2^(-2) = 4 + 1 + 1/4
a) 2^2 + 2^0 + 2^(-2) = 4 + 1 + 1/4 =21/4
a) 2^2 + 2^0 + 2^(-2) = 4 + 1 + 1/4 =21/4b) 10^(-1) + 10^0 + 10^3 = 1/10 + 1 +1000
a) 2^2 + 2^0 + 2^(-2) = 4 + 1 + 1/4 =21/4b) 10^(-1) + 10^0 + 10^3 = 1/10 + 1 +1000 = 1001.1
a) 100 =10^2
a) 100 =10^2b) 1000 = 10^3
a) 9^2 x 9^3 = 9^(2+3)
a) 9^2 x 9^3 = 9^(2+3) = 9^5
a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049
a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049b) 8 x 8^2 = 8^(1+3)
a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049b) 8 x 8^2 = 8^(1+3) = 8^4
a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049b) 8 x 8^2 = 8^(1+3) = 8^4 = 512
a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049b) 8 x 8^2 = 8^(1+3) = 8^4 = 512c) 7^5 ÷ 7^2 = 7^(5-2)
a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049b) 8 x 8^2 = 8^(1+3) = 8^4 = 512c) 7^5 ÷ 7^2 = 7^(5-2) = 7^3
a) 9^2 x 9^3 = 9^(2+3) = 9^5 = 59049b) 8 x 8^2 = 8^(1+3) = 8^4 = 512c) 7^5 ÷ 7^2 = 7^(5-2) = 7^3 = 343
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Answer:
Q10:
Apply the exponent rule that [tex]x^{-y} =\frac{1}{x^y}[/tex]
a) [tex]2^{-1} =\frac{1}{2^1}[/tex] = 0.5
b) [tex]4^{-1} =\frac{1}{4^1}[/tex] = 0.25
c) [tex]2^{-2}=\frac{1}{2^2} =\frac{1}{4}[/tex] = 0.25
Q11:
a) [tex]3^{-2} =\frac{1}{3^2} =\frac{1}{9}[/tex]
b) [tex]2^{-3} =\frac{1}{2^3} =\frac{1}{8}[/tex]
c) [tex]6^{-1} =\frac{1}{6^1}= \frac{1}{6}[/tex]
Q12:
a) [tex]2^2+2^0+2^{-2}=4+1+\frac{1}{4} =\frac{21}{4}[/tex]
b) [tex]10^{-1} +10^{0}+10^{-3}=\frac{1}{10}+1+1000=\frac{10011}{10}[/tex]
Q13:
a) [tex]100=10^{2}[/tex]
b) [tex]1000=10^{3}[/tex]
c) [tex]0.01=10^{-2}[/tex]
Q14:
a) [tex]9^{2}*9^{3}=9^{2+3}=9^{5}[/tex]
b) [tex]8*8^{2}=8^{1+2}=8^{3}[/tex]
c) [tex]7^{5}[/tex] ÷ [tex]7^{2}=7^{5-2}=7^{3}[/tex]