The required vertex of the given equation 8x²-64x will be at (4, -128)
How to find the vertex of an equation
Given the equation expressed as:
g(x) = 8x^2 – 64x
Factor out the greatest common factor of 8 to have:
g(x) = 8(x^2 - 8)
g(x) = 8(x^2-8x+4)-4
g(x)=8[(x-4)^2-4]
Hence the required vertex will be at (4, -128)
Learn more on vertex here: https://brainly.com/question/525947
