Answer:
8
Step-by-step explanation:
if we take the 2 that is in the R.H.S and put it in L.H.S
it becomes 16÷2=8
The quadratic equation in one variable x² = 16, will have solutions at the values of x = 4, -4.
Any equation of the form ax² + bx + c = 0, where a, b, and c are constants, a ≠ 0, and x is a variable, is a quadratic equation in one variable, x. a ≠ 0, because if a = 0, x² term will be missing and the equation will become a linear equation in one variable, x.
We have been given a quadratic equation in one variable: x² = 16.
We have been asked for the values of x, which are the solutions to the given equation.
We solve the equation by following steps:
Subtract 16 from both sides of the equation to get,
x² = 16
or, x² - 16 = 16 - 16
or, x² - 16 = 0
or, x² - 4² = 0.
We factorize this using the formula a² - b² = (a + b)(a - b) taking a = x, and b = 4.
∴ x² - 4² = 0
or, (x + 4)(x - 4) = 0.
By the zero-product law, we know that if A*B = 0, then either A = 0, or B = 0, or both A and B = 0.
∴ Either, x + 4 = 0. ⇒ x = -4
Or, x - 4 = 0. ⇒ x = 4.
∴ The quadratic equation in one variable x² = 16, will have solutions at the values of x = 4, -4.
Learn more about the quadratic equations in one variable at
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