Calculate the atomic mass of an element if 60.4% of the atoms have a mass of 68.9257 amu and the rest have a mass of 70.9249 amu. Identify the element in the periodic table.

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Answer

Explanation

     

Atomic mass =  abundances1 x relative mass 1+ abundances 2 x relative mass 2 ...etc

   =  ( 60.4% x 68.9257 + 39.6% x 70.9249)

    = 0.604 x 68.9257  +  0.396 x 70.9249)

     =  69.72 amu

The element with 2 isotopes, one representing 60.4 % of the atoms (68.9257 amu) and the other representing the rest (70.9249 amu), has an atomic mass of 69.7 amu. The element is Gallium.

An element has 2 isotopes. The sum of their abundances is 100%. If the abundance of isotope 1 is 60.4%, the abundance of isotope 2 is:

[tex]ab_1 + ab_2 = 100 \% \\ab_2 = 100\% - ab_1 = 100 \% - 60.4 \% = 39.6 \%[/tex]

Isotope 1 has an abundance of 60.4% and a mass of 68.9257 amu, while Isotope 2 has an abundance of 39.6% and a mass of 70.9249 amu. The atomic mass is the weighted average of the mass by the abundance.

[tex]am = \frac{68.9257 amu \times 60.4 + 70.9249 amu \times 39.6 }{100} = 69.7 amu[/tex]

The element with this atomic mass is Gallium.

The element with 2 isotopes, one representing 60.4 % of the atoms (68.9257 amu) and the other representing the rest (70.9249 amu), has an atomic mass of 69.7 amu. The element is Gallium.

You can learn more about isotopes here: https://brainly.com/question/21536220

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