Answer:
The value is [tex]v = 440 \ cm[/tex]
and
[tex]m = 16[/tex]
Explanation:
From the question we are told that
The image distance is [tex]v = 29 \ cm[/tex]
The focal length is [tex]f = -31 \ cm[/tex]
From the lens equation we have that
[tex]\frac{1}{f} = \frac{1}{v} - \frac{1}{u}[/tex]
=> [tex]\frac{1}{-31} = \frac{1}{v} - \frac{1}{29}[/tex]
=> [tex]v = 450 \ cm[/tex]
Generally the magnification is
[tex]m = \frac{v}{u}[/tex]
=> [tex]m = \frac{ 450}{29}[/tex]
=> [tex]m = 16[/tex]
