Answer:
20 m
Explanation:
Given that,
A book taken 2 s to strike the ground below.
We need to find how high is the balcony of the church. Let is assume that the book was at rest initially.
Using second equation of motion as follows :
[tex]d=ut+\dfrac{1}{2}at^2\\\\\text{Put u=0 and a = g}\\\\d=\dfrac{1}{2}\times 10\times 2^2\\\\d=20\ m[/tex]
Hence, the balcony of the church is at a height of 20 m.
