Respuesta :
Answer:
Temperature of the air in the balloon = 272°C
Explanation:
Given:
Volume of balloon = 500 m³
Air temperature = 15° C = 273 + 15 = 288 K
Total weight = 290 kg
Density of air = 1.23 kg/m³
Find:
Temperature of the air in the balloon
Computation:
Density of hot air = Density of air - [Total weight / Volume of balloon]
Density of hot air = 1.23 - [290 - 500]
Density of hot air = 0.65 kg/m³
[Density of hot air][Temperature of the air in the balloon] = [Density of air][Air temperature ]
Temperature of the air in the balloon = [(1.23)(288)]/(0.65)
Temperature of the air in the balloon = 544.98
Temperature of the air in the balloon = 545 K
Temperature of the air in the balloon = 545 - 273 = 272°C
Temperature of the air in the balloon to lift a total load of 290 kg is 272°C.
What is temperature?
Temperature is the degree of hotness or coldness of the object.
Given is Volume of balloon = 500 m³, Air temperature = 15° C = 273 + 15 = 288 K
Total weight = 290 kg and Density of air = 1.23 kg/m³
Density of hot air = Density of air - [Total weight / Volume of balloon]
Density of hot air = 1.23 - [290 - 500]
Density of hot air = 0.65 kg/m³
Density is inversely proportional to the temperature.
[ρ hot air] x [T air in the balloon] = [ρ air] x [T air ]
Putting the values, we get temperature of the air in the balloon is
T air = [(1.23)(288)]/(0.65)
T air in Kelvin is 545 K
T air in Celcius is 545 - 273 = 272°C.
Thus, the temperature of the air in balloon is 272°C.
Learn more about temperature.
https://brainly.com/question/11464844
#SPJ5
