Answer:
[tex]1.09nL[/tex]
Explanation:
Hello,
In this case, given that 1 gal equals 4 qt, 1 qt equals 0.9464 L and 1 L equals 1x10⁹ nL, the dimensional analysis turns out:
[tex]2.87x10^{-10}gal*\frac{4qt}{1gal} *\frac{0.9464L}{1qt}*\frac{1x10^9nL}{1L}\\ \\1.09nL[/tex]
Best regards.