Answer:
The binding energy released is 1.992 X 10⁻¹⁸ J
Explanation:
Given;
mass of the alpha particle, m = 6.64 x 10⁻²⁷ kg
speed of the alpha particle, c = 3 x 10⁸ m/s
The binding energy released is given by;
[tex]E_b = mc^2[/tex]
where;
m is mass of the particle
c is speed of the particle
E = 6.64 x 10⁻²⁷ (3 x 10⁸)²
E = 1.992 X 10⁻¹⁸ J
Therefore, the binding energy released is 1.992 X 10⁻¹⁸ J
