Respuesta :
Answer: [tex]3r+8<-12[/tex].
Step-by-step explanation:
It is given that three times a number r plus 8 is fewer than −12.
We need to write the sentence as an inequality.
Three times a number r = 3r
Times a number r plus 8 = 3r+8
Fewer than = less than = <
So, the inequality for the sentence "three times a number r plus 8 is fewer than −12" is
[tex]3r+8<-12[/tex]
Therefore, the required inequality is [tex]3r+8<-12[/tex].
The inequality that describes the sentence is:
[tex]3r + 8 < -12[/tex]
--------------------------------
- 3 times 1 is [tex]3 \times 1 = 3[/tex], 3 times 2 is [tex]3 \times 2 = 6[/tex], and so on, thus 3 times a number r is [tex]3 \times r = 3r[/tex].
- The plus word means that we have an addition operation, plus 8, thus [tex]3r + 8[/tex]
- Fewer than -12 means that the less than -12 completes the inequality, thus:
[tex]3r + 8 < -12[/tex]
Which is the inequality that describes this situation.
A similar problem is given at https://brainly.com/question/13094243
