Answer:
1 m/s.
Explanation:
Given that,
Mass of a cue stick, m₁ = 0.5 kg
Mass of a ball, m₂ = 0.2 kg
The cue stick hits a ball with a velocity of 2.5 m/s
We need to find the velocity of the ball after it is hit. Tn this problem, the momentum of the system remains conserved. So,
m₁v₁ = m₂v₂
⇒ [tex]v_1=\dfrac{m_2v_2}{m_1}\\\\v_1=\dfrac{0.2\times 2.5}{0.5}\\\\v_1=1\ m/s[/tex]
So, the velocity of the ball after it is hit is 1 m/s.
